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Calculate the value of tan(4π/3) on the unit circle

Calculate the value of tan(4π/3) on the unit circle

First, let’s understand the position of $\frac{4\pi}{3}$ on the unit circle. The angle $\frac{4\pi}{3}$ radians is in the third quadrant.

In the third quadrant, the reference angle is $\frac{\pi}{3}$. The tangent is positive in the third quadrant.

We know that $\tan\left(\frac{\pi}{3}\right) = \sqrt{3}$. Therefore:

$$ \tan\left(\frac{4\pi}{3}\right) = \tan\left(\pi + \frac{\pi}{3}\right) = \tan\left(\frac{\pi}{3}\right) = \sqrt{3} $$

Find the sine and cosine of the angle 30 degrees using the unit circle

Find the sine and cosine of the angle 30 degrees using the unit circle

First, we need to convert $30^{\circ}$ to radians:

$$30^{\circ} = 30 \times \frac{\pi}{180} = \frac{\pi}{6}$$

On the unit circle, the coordinates of the angle $\frac{\pi}{6}$ are:

$$\left( \cos\left(\frac{\pi}{6}\right), \sin\left(\frac{\pi}{6}\right) \right)$$

Using known values, we have:

$$\cos\left(\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2}$$

$$\sin\left(\frac{\pi}{6}\right) = \frac{1}{2}$$

Therefore, the sine of $30^{\circ}$ is $\frac{1}{2}$ and the cosine of $30^{\circ}$ is $\frac{\sqrt{3}}{2}$.

Calculate the exact value of sin(5π/6) and verify it on the unit circle

Calculate the exact value of sin(5π/6) and verify it on the unit circle

To find the exact value of $\sin(\frac{5π}{6})$, we first determine the corresponding angle in degrees. Converting radians to degrees:

$$\frac{5π}{6} \times \frac{180^\circ}{π} = 150^\circ$$

Now, considering the unit circle, the angle $150^\circ$ lies in the second quadrant where the sine value is positive. The reference angle for $150^\circ$ is:

$$180^\circ – 150^\circ = 30^\circ$$

We know from the unit circle that:

$$\sin(30^\circ) = \frac{1}{2}$$

Therefore,

$$\sin(150^\circ) = \sin(\frac{5π}{6}) = \frac{1}{2}$$

Find the sine of π/6 on the unit circle

Find the sine of π/6 on the unit circle

To find the sine of $\frac{\pi}{6}$ on the unit circle, we need to know the coordinates of the point on the unit circle corresponding to this angle. The unit circle has a radius of 1, and an angle of $\frac{\pi}{6}$ corresponds to 30 degrees in the first quadrant.

The coordinates of this point on the unit circle are $\left( \frac{\sqrt{3}}{2}, \frac{1}{2} \right)$. The y-coordinate of this point gives us the sine value.

Therefore,

$$ \sin\left(\frac{\pi}{6}\right) = \frac{1}{2} $$

Given a unit circle centered at the origin, find the coordinates of a point P on the circle such that the angle θ between the line segment OP and the positive x-axis is an irrational multiple of π

Given a unit circle centered at the origin, find the coordinates of a point P on the circle such that the angle θ between the line segment OP and the positive x-axis is an irrational multiple of π

To solve this problem, we need to find the coordinates of point $P$ on the unit circle given that the angle $\theta$ is an irrational multiple of $\pi$. Let’s denote this angle as $\theta = k\pi$ where $k$ is an irrational number.

Using the parametric equations of the unit circle, we have:

$$x = \cos(\theta)$$

$$y = \sin(\theta)$$

Since $\theta$ is an irrational multiple of $\pi$, we can choose $\theta = \sqrt{2}\pi$. Then, the coordinates $(x,y)$ of point $P$ are:

$$x = \cos(\sqrt{2}\pi)$$

$$y = \sin(\sqrt{2}\pi)$$

Thus, the coordinates of $P$ are:

$$P = (\cos(\sqrt{2}\pi), \sin(\sqrt{2}\pi))$$

Find the sine and cosine values for an angle of 45 degrees on the unit circle

Find the sine and cosine values for an angle of 45 degrees on the unit circle

Using the unit circle, we can determine the sine and cosine values of $45^\circ$.

$45^\circ$ (or $\frac{\pi}{4}$ radians) is a commonly known angle.

The coordinates of the point on the unit circle corresponding to $45^\circ$ are $(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$.

Therefore, the sine value is $\sin(45^\circ) = \frac{\sqrt{2}}{2}$ and the cosine value is $\cos(45^\circ) = \frac{\sqrt{2}}{2}$.

Find the Cartesian coordinates of a point on the unit circle at a given angle

Find the Cartesian coordinates of a point on the unit circle at a given angle

First, recall that for any point on the unit circle, its coordinates can be represented as \((x, y) = (\cos \theta, \sin \theta)\).

Given an angle \(\theta = \frac{3\pi}{4}\), we can calculate the coordinates as follows:

$$ x = \cos \left( \frac{3\pi}{4} \right) = \cos \left(135^\circ \right) = -\frac{\sqrt{2}}{2} $$

$$ y = \sin \left( \frac{3\pi}{4} \right) = \sin \left(135^\circ \right) = \frac{\sqrt{2}}{2} $$

Therefore, the Cartesian coordinates of the point are \( \left( -\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right) \).

Convert 135 degrees to radians and find the sine and cosine values

Convert 135 degrees to radians and find the sine and cosine values

To convert 135 degrees to radians, we use the formula:

$$\text{Radians} = \text{Degrees} \times \frac{\pi}{180}$$

So,

$$135 \times \frac{\pi}{180} = \frac{135\pi}{180} = \frac{3\pi}{4}$$

Next, we find the sine and cosine values for $\frac{3\pi}{4}$:

$$\sin\left(\frac{3\pi}{4}\right) = \sin\left(\pi – \frac{\pi}{4}\right) = \sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}$$

$$\cos\left(\frac{3\pi}{4}\right) = \cos\left(\pi – \frac{\pi}{4}\right) = -\cos\left(\frac{\pi}{4}\right) = -\frac{\sqrt{2}}{2}$$

Therefore,

$$\text{Radians} = \frac{3\pi}{4}, \sin = \frac{\sqrt{2}}{2}, \cos = -\frac{\sqrt{2}}{2}$$

Determine the value of tan for given angles on the unit circle

Determine the value of tan for given angles on the unit circle

$$\text{Given an angle of } \theta = \frac{5\pi}{4}$$

We know that:

$$\tan \theta = \frac{\sin \theta}{\cos \theta}$$

On the unit circle, for \(\theta = \frac{5\pi}{4}, \sin \theta = -\frac{\sqrt{2}}{2} \) and \(\cos \theta = -\frac{\sqrt{2}}{2}\)

Therefore,

$$\tan \left(\frac{5\pi}{4}\right) = \frac{-\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}}$$

Simplifying, we get:

$$\tan \left(\frac{5\pi}{4}\right) = 1$$

Find the value of tan(θ) on the unit circle when θ = π/4

Find the value of tan(θ) on the unit circle when θ = π/4

First, we need to determine the coordinates of the point on the unit circle corresponding to $\theta = \frac{\pi}{4}$.

On the unit circle, the coordinates for the angle $\frac{\pi}{4}$ are $\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)$.

The tangent of an angle $\theta$ is given by the ratio of the y-coordinate to the x-coordinate of the corresponding point on the unit circle:

$$\tan\left(\frac{\pi}{4}\right) = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$$

So, the value of $\tan(\theta)$ for $\theta = \frac{\pi}{4}$ is 1.

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