”How
Answer 1
Holly Jones PhD
To solve 2sin(x)cos(x) = sin(x) within [0, 2π], first use the identity 2sin(x)cos(x) = sin(2x). The equation becomes sin(2x) = sin(x). This implies two cases: 2x = x + 2kπ or 2x = π – x + 2kπ. Solving these gives x = 0, π, 2π, π/3, 5π/3.
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