Given the unit circle, find the coordinates of the point where the angle $ heta$ intersects the unit circle. Let $ heta = 45^circ$.
Answer 1
Emma Johnson
To find the coordinates of the point where the angle $\theta = 45^\circ$ intersects the unit circle, we use the fact that the unit circle has a radius of 1. The coordinates on the unit circle are given by $(\cos \theta, \sin \theta)$.
$\cos 45^\circ = \frac{\sqrt{2}}{2} $
$\sin 45^\circ = \frac{\sqrt{2}}{2}$
Thus, the coordinates are $\left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right)$.
Answer 2
James Taylor
To determine the coordinates where angle $ heta = 45^circ$ intersects the unit circle, recall that each point on the unit circle can be represented as $(cos heta, sin heta)$.
For $ heta = 45^circ$,
$cos 45^circ = sin 45^circ = frac{sqrt{2}}{2}$
So, the coordinates are
$left( frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)$.
Answer 3
Isabella Walker
The coordinates of the point on the unit circle where $ heta = 45^circ$ intersect can be found using $(cos heta, sin heta)$.
Since $cos 45^circ = sin 45^circ = frac{sqrt{2}}{2}$, the coordinates are
$left( frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)$.
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