Find the value of $sec(frac{pi}{3})$ on the unit circle.
Answer 1
Lucas Brown
To find $\sec(\frac{\pi}{3})$, we first need to find $\cos(\frac{\pi}{3})$ since $\sec(\theta) = \frac{1}{\cos(\theta)}$.
On the unit circle, for $\theta = \frac{\pi}{3}$, we have $\cos(\frac{\pi}{3}) = \frac{1}{2}$.
Therefore, $\sec(\frac{\pi}{3}) = \frac{1}{\cos(\frac{\pi}{3})} = \frac{1}{\frac{1}{2}} = 2$.
So, $\sec(\frac{\pi}{3}) = 2$.
Answer 2
Joseph Robinson
We start with knowing that $sec(frac{pi}{3}) = frac{1}{cos(frac{pi}{3})}$.
On the unit circle, $cos(frac{pi}{3})$ is $frac{1}{2}$.
Thus, $sec(frac{pi}{3}) = frac{1}{frac{1}{2}} = 2$.
Hence, $sec(frac{pi}{3}) = 2$.
Answer 3
John Anderson
$sec(frac{pi}{3}) = frac{1}{cos(frac{pi}{3})}$.
$cos(frac{pi}{3}) = frac{1}{2}$.
$sec(frac{pi}{3}) = 2$.
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