Find the value of $ arcsin(frac{1}{2}) $.
Answer 1
Ava Martin
To find the value of $ \arcsin(\frac{1}{2}) $, we need to determine the angle $ \theta $ whose sine is $ \frac{1}{2} $.
From the unit circle, we know:
$ \sin(\theta) = \frac{1}{2} $
The angle $ \theta $ that satisfies this in the range $ [-\frac{\pi}{2}, \frac{\pi}{2}] $ is:
$ \theta = \frac{\pi}{6} $
Thus, $ \arcsin(\frac{1}{2}) = \frac{\pi}{6} $.
Answer 2
Chloe Evans
To determine the value of $ arcsin(frac{1}{2}) $, use the unit circle:
$ sin( heta) = frac{1}{2} $
Within $ [-frac{pi}{2}, frac{pi}{2}] $, the angle $ heta $ is:
$ heta = frac{pi}{6} $
So, $ arcsin(frac{1}{2}) = frac{pi}{6} $.
Answer 3
Abigail Nelson
From the unit circle,
$ arcsin(frac{1}{2}) = frac{pi}{6} $
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