Find the terminal point on the unit circle for an angle of $ frac{pi}{6} $ radians
Answer 1
Emily Hall
To find the terminal point on the unit circle for an angle of $ \frac{\pi}{6} $ radians, we use the unit circle definition:
The coordinates are given by $ ( \cos( \theta ), \sin( \theta ) ) $.
For $ \theta = \frac{\pi}{6} $:
$ \cos( \frac{\pi}{6} ) = \frac{\sqrt{3}}{2} $
$ \sin( \frac{\pi}{6} ) = \frac{1}{2} $
So, the terminal point is:
$( \frac{\sqrt{3}}{2}, \frac{1}{2} )$
Answer 2
Isabella Walker
For an angle $ frac{pi}{6} $ radians on the unit circle, the terminal point coordinates are:
The coordinates are $ ( cos( heta ), sin( heta ) ) $.
For $ heta = frac{pi}{6} $:
$ cos( frac{pi}{6} ) = frac{sqrt{3}}{2} $
$ sin( frac{pi}{6} ) = frac{1}{2} $
Thus, the terminal point is:
$( frac{sqrt{3}}{2}, frac{1}{2} )$
Answer 3
James Taylor
The terminal point for $ frac{pi}{6} $ radians on the unit circle has coordinates:
$( cos( frac{pi}{6} ), sin( frac{pi}{6} ) ) = ( frac{sqrt{3}}{2}, frac{1}{2} )$
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