”Find

First, we start from the given equation:

$ 2\sin(\theta)\cos(\theta) = 1 $

We recognize that:

$ 2\sin(\theta)\cos(\theta) = \sin(2\theta) $

So the equation becomes:

$ \sin(2\theta) = 1 $

Since $ \sin(\frac{\pi}{2}) = 1 $, we have:

$ 2\theta = \frac{\pi}{2} $

Thus:

$ \theta = \frac{\pi}{4} $

Finally, we find that:

$ \tan\left(\frac{\pi}{4}\right) = 1 $

Given:

$ 2sin( heta)cos( heta) = 1 $

Rewrite using the double-angle identity:

$ sin(2 heta) = 1 $

Since $ sin(2 heta) = 1 $ when $ 2 heta = frac{pi}{2} $, we have:

$ heta = frac{pi}{4} $

Therefore:

$ anleft(frac{pi}{4}
ight) = 1 $

Given $ 2sin( heta)cos( heta) = 1 $, use:

$ sin(2 heta) = 1 $

Then $ heta = frac{pi}{4} $:

$ anleft(frac{pi}{4}
ight) = 1 $

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