Find the angle on the unit circle corresponding to $ arctanleft(frac{1}{sqrt{3}}
ight) $

Given $ \arctan\left(\frac{1}{\sqrt{3}}\right) $, we need to determine the angle $ \theta $ on the unit circle.

We know that $ \arctan(x) $ gives the angle whose tangent is $ x $. Hence:

$ \tan(\theta) = \frac{1}{\sqrt{3}} $

We recognize that the angle corresponding to this tangent value is:

$ \theta = \frac{\pi}{6} $

Thus, the angle on the unit circle is $ \frac{\pi}{6} $.

Given $ arctanleft(frac{1}{sqrt{3}}
ight) $, we need to find the angle $ heta $ such that:

$ an( heta) = frac{1}{sqrt{3}} $

From trigonometric identities, we know this occurs at:

$ heta = frac{pi}{6} $

Thus, the angle is $ frac{pi}{6} $.

For $ arctanleft(frac{1}{sqrt{3}}
ight) $, the angle $ heta $ is:

$ heta = frac{pi}{6} $

Start Using PopAi Today