Calculate the coordinates of a point on the unit circle at an angle of $ frac{5pi}{6} $
Answer 1
Michael Moore
To find the coordinates of a point on the unit circle at an angle of $ \frac{5\pi}{6} $, we use the unit circle properties.
In the unit circle, the coordinates of a point at an angle $ \theta $ are given by $ ( \cos(\theta), \sin(\theta) ) $.
So for $ \theta = \frac{5\pi}{6} $:
$ \cos(\frac{5\pi}{6}) = -\frac{ \sqrt{3} }{2} $
$ \sin(\frac{5\pi}{6}) = \frac{1}{2} $
Therefore, the coordinates are:
$ \left( -\frac{ \sqrt{3} }{2}, \frac{1}{2} \right) $
Answer 2
Matthew Carter
The coordinates on the unit circle at an angle of $ frac{5pi}{6} $ are found using:
$ left( cos(frac{5pi}{6}), sin(frac{5pi}{6})
ight) $
Calculating these gives:
$ cos(frac{5pi}{6}) = -frac{ sqrt{3} }{2} $
$ sin(frac{5pi}{6}) = frac{1}{2} $
The coordinates are:
$ left( -frac{ sqrt{3} }{2}, frac{1}{2}
ight) $
Answer 3
Maria Rodriguez
The coordinates of the point at an angle of $ frac{5pi}{6} $ are:
$ left( -frac{ sqrt{3} }{2}, frac{1}{2}
ight) $
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