$Understanding ; the ; representation ; of ; sine ; on ; the ; unit ; circle$
Answer 1
To understand what sine represents on the unit circle, let’s begin with the definition of the unit circle. The unit circle is a circle with a radius of 1 centered at the origin of the coordinate system.
Consider a point $P(x, y)$ on the unit circle that forms an angle $\theta$ with the positive x-axis. The coordinates of point $P$ can be expressed in terms of trigonometric functions as:
$x = \cos(\theta)$
$y = \sin(\theta)$
Therefore, the sine of the angle $\theta$ is the y-coordinate of the corresponding point on the unit circle.
To elaborate with a specific angle, let’s consider $\theta = \frac{\pi}{4}$. The coordinates of the point on the unit circle at this angle are:
$P\left( \cos\left(\frac{\pi}{4}\right), \sin\left(\frac{\pi}{4}\right)\right) = P\left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right)$
Thus, for $\theta = \frac{\pi}{4}$, the sine value is:
$\sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}$
This demonstrates that sine represents the y-coordinate of a point on the unit circle corresponding to a given angle.
Answer 2
To understand the representation of sine on the unit circle, we need to explore the trigonometric definition and how angles relate to coordinates.
The unit circle is a circle centered at the origin $(0,0)$ with a radius of 1. For an angle $ heta$ measured from the positive x-axis, the coordinates $(x, y)$ of the point on the unit circle are given by:
$x = cos( heta)$
$y = sin( heta)$
Thus, the sine of angle $ heta$ is the y-coordinate of the corresponding point. This means that if you move around the unit circle, the y-coordinate of the point at any angle $ heta$ will be $sin( heta)$.
For example, let’s take $ heta = frac{pi}{3}$. The coordinates of this point on the unit circle can be found as follows:
$Pleft( cosleft(frac{pi}{3}
ight), sinleft(frac{pi}{3}
ight)
ight) = Pleft( frac{1}{2}, frac{sqrt{3}}{2}
ight)$
Thus, for $ heta = frac{pi}{3}$, the sine value is:
$sinleft(frac{pi}{3}
ight) = frac{sqrt{3}}{2}$
This confirms that the sine function represents the y-coordinate of a specific point on the unit circle.
Answer 3
The unit circle is a circle with a radius of 1 centered at the origin. For any angle $ heta$, the coordinates of a point on the unit circle are $(cos( heta), sin( heta))$.
Therefore, the sine of angle $ heta$ is the y-coordinate of the corresponding point on the unit circle.
For instance, at $ heta = frac{pi}{6}$:
$sinleft(frac{pi}{6}
ight) = frac{1}{2}$
This shows that sine represents the y-coordinate of a point on the unit circle at angle $ heta$.
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