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How do you solve for x in the equation 3x + 7 = 25?

How do you solve for x in the equation 3x + 7 = 25?To solve for x in the equation 3x + 7 = 25, subtract 7 from both sides to get 3x = 18. Then, divide both sides by 3 to isolate x, resulting in x = 6.

How do you find the limit of a function as it approaches infinity when the function involves a quotient of polynomials?

How do you find the limit of a function as it approaches infinity when the function involves a quotient of polynomials?To find the limit of a quotient of polynomials as the variable approaches infinity, compare the degrees of the numerator and the denominator. If the degree of the numerator is less, the limit is zero. If equal, the limit is the ratio of leading coefficients. If greater, the limit is infinity or negative infinity.

How do you derive the formula for the volume of a solid of revolution using the method of cylindrical shells versus the disk method?

How do you derive the formula for the volume of a solid of revolution using the method of cylindrical shells versus the disk method?The disk method involves slicing the solid perpendicular to the axis of revolution and summing the volumes of disks. The volume is given by V = ∫[a to b] π[f(x)]^2 dx. The method of cylindrical shells involves slicing the solid parallel to the axis of revolution, summing the volumes of cylindrical shells. The volume is given by V = ∫[a to b] 2πx[f(x)] dx.

How do you find the maximum and minimum values of a function using the first and second derivatives?

How do you find the maximum and minimum values of a function using the first and second derivatives?To find the maximum and minimum values of a function using the first and second derivatives, follow these steps: 1. Find the first derivative of the function and set it to zero to solve for critical points. 2. Use the second derivative test: if the second derivative at a critical point is positive, it’s a local minimum; if negative, it’s a local maximum. If the second derivative is zero, the test is inconclusive.

How do you interpret the results of a hypothesis test, including p-values and confidence intervals, in the context of a given real-world data set?

How do you interpret the results of a hypothesis test, including p-values and confidence intervals, in the context of a given real-world data set?Interpreting hypothesis test results involves evaluating the p-value and confidence interval. A p-value indicates the probability of observing the data if the null hypothesis is true. A low p-value (typically < 0.05) suggests rejecting the null hypothesis. Confidence intervals provide a range of plausible values for the parameter, indicating the precision and reliability of the estimate. If the confidence interval does not include the null hypothesis value, it supports rejecting the null hypothesis.

Let’s solve for the values of x that satisfy the following equation: √(x + 4) – 3 = x – 2.

Let’s solve for the values of x that satisfy the following equation: √(x + 4) – 3 = x – 2.To solve the equation √(x + 4) – 3 = x – 2, first isolate the square root term: √(x + 4) = x + 1. Then, square both sides to eliminate the square root: x + 4 = (x + 1)². Simplify and solve the resulting quadratic equation: x² – x – 3 = 0. The solutions are x = 3 and x = -1. Verify both solutions in the original equation to ensure they are valid.

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