$In which quadrant does the angle lie on the unit circle?$
Answer 1
Mia Harris
$Given \ an \ angle \ of \ 150^{\circ}, \ we \ need \ to \ determine \ which \ quadrant \ it \ lies \ in.$
$Quadrant \, I: \ 0^{\circ} \leq \theta < 90^{\circ}$
$Quadrant \, II: \ 90^{\circ} \leq \theta < 180^{\circ}$
$Quadrant \, III: \ 180^{\circ} \leq \theta < 270^{\circ}$
$Quadrant \, IV: \ 270^{\circ} \leq \theta < 360^{\circ}$
$Since \ 150^{\circ} \ lies \ between \ 90^{\circ} \ and \ 180^{\circ}, \ it \ is \ in \ Quadrant \, II.$
Answer 2
Chloe Evans
$Determine the quadrant for an angle of -45^{circ}.$
$Quadrant , I: 0^{circ} leq heta < 90^{circ}$
$Quadrant , II: 90^{circ} leq heta < 180^{circ}$
$Quadrant , III: 180^{circ} leq heta < 270^{circ}$
$Quadrant , IV: 270^{circ} leq heta < 360^{circ}$
$Since -45^{circ} is equivalent to 315^{circ} (360^{circ} – 45^{circ}), it lies in Quadrant , IV.$
Answer 3
Benjamin Clark
$Find the quadrant for an angle of 210^{circ}.$
$Quadrant , I: 0^{circ} leq heta < 90^{circ}$
$Quadrant , II: 90^{circ} leq heta < 180^{circ}$
$Quadrant , III: 180^{circ} leq heta < 270^{circ}$
$Quadrant , IV: 270^{circ} leq heta < 360^{circ}$
$Since 210^{circ} lies between 180^{circ} and 270^{circ}, it is in Quadrant , III.$
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