If an object leaves City A, traveling towards City B at a constant speed of x miles per hour, and another object leaves City B, traveling towards City A at a constant speed that is 5 miles per hour faster than the object's speed from City A, if the distan
Answer 1
Let the speed of the object from City A be x mph. The speed of the object from City B is (x + 5) mph. The combined speed is x + (x + 5) = 2x + 5 mph. The time to meet is 200 / (2x + 5) hours.
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