How do you solve the equation 3x^2 - 2x + 1 = 0 using the quadratic formula?
Answer 1
To solve the equation 3x^2 – 2x + 1 = 0 using the quadratic formula, use x = (-b ± √(b² – 4ac)) / 2a. Here, a = 3, b = -2, and c = 1. Calculate the discriminant (b² – 4ac): (-2)² – 4(3)(1) = 4 – 12 = -8. Since the discriminant is negative, the equation has two complex solutions: x = (2 ± √(-8)) / 6 = (2 ± 2i√2) / 6 = 1/3 ± i√2/3.
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