How do you solve the equation 2x^2 + 3x - 5 = 0 using the quadratic formula?
Answer 1
Kelly Leblanc
To solve the quadratic equation 2x^2 + 3x – 5 = 0 using the quadratic formula, we use the formula x = [-b ± sqrt(b^2 – 4ac)] / 2a. Here, a = 2, b = 3, and c = -5. Plugging in these values, we get x = [-3 ± sqrt(3^2 – 4*2*(-5))] / (2*2). Simplifying, we find x = [-3 ± sqrt(9 + 40)] / 4, or x = [-3 ± sqrt(49)] / 4. Therefore, x = [-3 ± 7] / 4, giving us two solutions: x = 1 and x = -5/2.
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