How do you prove that the angle subtended by an arc in a circle is equal to half the angle subtended by the same arc when measured at the center of the circle?
Answer 1
To prove that the angle subtended by an arc at the circumference of a circle is half the angle subtended by the same arc at the center, consider a circle with center O. Let points A, B, and C lie on the circle such that arc AC subtends angle ∠AOC at the center and angle ∠ABC at the circumference. By the Inscribed Angle Theorem, ∠ABC = 1/2 ∠AOC. This is because the angle at the center is formed by two radii, while the angle at the circumference is formed by a chord and a secant, making the central angle double the inscribed angle.
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