How do you find the amplitude and period of the function y = 3sin(2x - π)?
Answer 1
To find the amplitude and period of the function y = 3sin(2x – π), first identify the amplitude, which is the coefficient of the sine function, here it is 3. The period is determined by the coefficient of x inside the sine function. The period of sin(Bx) is given by (2π)/B. For y = 3sin(2x – π), B is 2, so the period is (2π)/2 = π.
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