”Given
Answer 1
We start by setting the equation:
$\sin(\theta) = \cos(\theta)$
We know from trigonometric identities that:
$\sin(\theta) = \cos(\theta)$
Dividing both sides by $\cos(\theta)$ (assuming $\cos(\theta) \neq 0$):
$\frac{\sin(\theta)}{\cos(\theta)} = 1$
Using the identity $\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$, we get:
$\tan(\theta) = 1$
This implies that:
$\theta = \frac{\pi}{4} + k\pi \text{ for some integer } k$
Since we need $\theta$ in the interval $[0, 2\pi)$, we find:
$\theta = \frac{\pi}{4} \text{ or } \theta = \frac{5\pi}{4}$
Therefore, the angles $\theta$ are:
$\theta = \frac{\pi}{4} \text{ and } \theta = \frac{5\pi}{4}$
Answer 2
To solve $sin( heta) = cos( heta)$, we consider the unit circle where $sin( heta)$ and $cos( heta)$ are equal.
As these functions are equal when $ heta = frac{pi}{4}$ and $ heta = frac{5pi}{4}$, we can solve for $ heta$ by examining:
$sin( heta) – cos( heta) = 0$
This leads us to:
$sin( heta) = cos( heta)$
Or equivalently:
$ an( heta) = 1$
Thus:
$ heta = frac{pi}{4} + npi , ext{for}, n in mathbb{Z}$
Within the interval $[0, 2pi)$, the valid angles are:
$ heta = frac{pi}{4} ext{ and } heta = frac{5pi}{4}$
Answer 3
Given $sin( heta) = cos( heta)$, we divide both sides by $cos( heta)$:
$frac{sin( heta)}{cos( heta)} = 1$
Therefore, $ an( heta) = 1$, leading to:
$ heta = frac{pi}{4} + kpi$
Within $[0, 2pi)$, we have:
$ heta = frac{pi}{4} ext{ and } heta = frac{5pi}{4}$
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