Given sin(a + b) = sin a * cos b + cos a * sin b and sin(a - b) = sin a * cos b - cos a * sin b, derive an expression for tan(a + b) in terms of tan a and tan b.

To derive tan(a + b) in terms of tan(a) and tan(b), we start with the given identities for sin(a + b) and cos(a + b). Using the identity tan(x) = sin(x)/cos(x), we get tan(a + b) = (tan(a) + tan(b)) / (1 – tan(a) * tan(b)).

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