$ ext{Given a point on the unit circle at coordinates } (sqrt{3}/2, -1/2), ext{ find the angle in radians, the corresponding angle in degrees, and the sine of the angle.}$

To find the angle in radians, we use the coordinates on the unit circle. The x-coordinate gives us $\cos(\theta) = \frac{\sqrt{3}}{2}$ and the y-coordinate gives us $\sin(\theta) = -\frac{1}{2}$. These coordinates correspond to an angle in the fourth quadrant. Therefore, the angle in radians is:

$\theta = -\frac{\pi}{6}$

To convert this to degrees, we use the conversion factor $\frac{180}{\pi}$:

$\theta = -\frac{\pi}{6} \times \frac{180}{\pi} = -30^\circ$

The sine of the angle is already given by the y-coordinate:

$\sin(\theta) = -\frac{1}{2}$

First, identify the angle with the given coordinates on the unit circle. Given $cos( heta) = frac{sqrt{3}}{2}$ and $sin( heta) = -frac{1}{2}$:

The coordinates match those of the angle in the fourth quadrant. Hence, the angle in radians is:

$ heta = -frac{pi}{6}$

To find the angle in degrees, multiply by $frac{180}{pi}$:

$ heta = -frac{pi}{6} imes frac{180}{pi} = -30^circ$

The sine value is given by the y-coordinate:

$sin( heta) = -frac{1}{2}$

The point (sqrt{3}/2, -1/2) corresponds to an angle in the fourth quadrant:

$ heta = -frac{pi}{6}$

In degrees:

$ heta = -30^circ$

The sine is:

$sin( heta) = -frac{1}{2}$

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