Finding the Coordinates on the Unit Circle
Answer 1
Given an angle of $\frac{5\pi}{4}$ radians, find the coordinates of the point on the unit circle.
Solution:
The unit circle has a radius of 1. The coordinates for any angle $\theta$ on the unit circle can be found using the formulas $\cos(\theta)$ and $\sin(\theta)$.
Here, $\theta = \frac{5\pi}{4}$.
First, find $\cos(\frac{5\pi}{4})$:
$ \cos(\frac{5\pi}{4}) = -\frac{\sqrt{2}}{2} $
Next, find $\sin(\frac{5\pi}{4})$:
$ \sin(\frac{5\pi}{4}) = -\frac{\sqrt{2}}{2} $
Therefore, the coordinates are:
$(\cos(\frac{5\pi}{4}), \sin(\frac{5\pi}{4})) = (-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2})$
Answer 2
Find the coordinates of the point on the unit circle corresponding to an angle of $frac{5pi}{4}$ radians.
Solution:
Using the unit circle, the coordinates for any angle $ heta$ are given by the pair $(cos( heta), sin( heta))$.
For $ heta = frac{5pi}{4}$:
Calculate $cos(frac{5pi}{4})$:
$ cos(frac{5pi}{4}) = -frac{sqrt{2}}{2} $
Calculate $sin(frac{5pi}{4})$:
$ sin(frac{5pi}{4}) = -frac{sqrt{2}}{2} $
Hence, the coordinates of the point are:
$(cos(frac{5pi}{4}), sin(frac{5pi}{4})) = (-frac{sqrt{2}}{2}, -frac{sqrt{2}}{2})$
Answer 3
For an angle of $frac{5pi}{4}$ radians, find the coordinates on the unit circle.
Solution:
The coordinates are $(cos(frac{5pi}{4}), sin(frac{5pi}{4}))$.
Therefore,
$ cos(frac{5pi}{4}) = -frac{sqrt{2}}{2} $
$ sin(frac{5pi}{4}) = -frac{sqrt{2}}{2} $
The coordinates are $(-frac{sqrt{2}}{2}, -frac{sqrt{2}}{2})$.
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