Find the value of $ an(θ) $ at $ θ = frac{3π}{4} $ on the unit circle
Answer 1
James Taylor
To find the value of $ \tan(θ) $ at $ θ = \frac{3π}{4} $, we first identify the coordinates on the unit circle:
At $ θ = \frac{3π}{4} $, the coordinates are $ (-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}) $.
So, $ \tan(θ) $ is given by:
$ \tan(θ) = \frac{y}{x} = \frac{\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = -1 $
Therefore, $ \tan(θ) = -1 $.
Answer 2
William King
To find $ an(θ) $ at $ θ = frac{3π}{4} $, note that the coordinates on the unit circle are $ (-frac{sqrt{2}}{2}, frac{sqrt{2}}{2}) $. Thus:
$ an(θ) = frac{y}{x} = frac{frac{sqrt{2}}{2}}{-frac{sqrt{2}}{2}} = -1 $
Answer 3
Alex Thompson
At $ θ = frac{3π}{4} $, the coordinates are $ (-frac{sqrt{2}}{2}, frac{sqrt{2}}{2}) $. Thus,
$ an(θ) = -1 $
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