Find the value of $sec( heta)$ when the point on the unit circle corresponding to $ heta$ is $(rac{1}{2}, rac{sqrt{3}}{2})$.
Answer 1
Given the point on the unit circle corresponding to $\\theta$ is $ (\\frac{1}{2}, \\frac{\\sqrt{3}}{2})$, we know
$\\cos(\\theta) = \\frac{1}{2}.$
Therefore,
$\\sec(\\theta) = \\frac{1}{\\cos(\\theta)} = \\frac{1}{\\frac{1}{2}} = 2.$
Answer 2
Given that $\cos(\theta) = \frac{1}{2}$ from the point $ (\frac{1}{2}, \frac{\sqrt{3}}{2})$, we have:
$\sec(\theta) = \frac{1}{\cos(\theta)}.$
Substituting the value, we get:
$\sec(\theta) = \frac{1}{\frac{1}{2}}.$
Simplifying, we find:
$\sec(\theta) = 2.$
Answer 3
The given point on the unit circle is $ (\frac{1}{2}, \frac{\sqrt{3}}{2})$. Therefore,
$\cos(\theta) = \frac{1}{2}.$
Thus,
$\sec(\theta) = 2.$
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