Find the coordinates of the point on the unit circle where the angle is $frac{5pi}{6}$.

To find the coordinates of the point on the unit circle where the angle is $\frac{5\pi}{6}$, we use the unit circle trigonometric identities for sine and cosine.

Since $\frac{5\pi}{6}$ is in the second quadrant:

The x-coordinate is:

$ x = \cos\left(\frac{5\pi}{6}\right) = -\frac{\sqrt{3}}{2} $

The y-coordinate is:

$ y = \sin\left(\frac{5\pi}{6}\right) = \frac{1}{2} $

So, the coordinates are:

$ \left( -\frac{\sqrt{3}}{2}, \frac{1}{2} \right) $

For an angle of $frac{5pi}{6}$ on the unit circle:

The x-coordinate is:

$ cosleft(frac{5pi}{6}
ight) = -frac{sqrt{3}}{2} $

The y-coordinate is:

$ sinleft(frac{5pi}{6}
ight) = frac{1}{2} $

Coordinates of $frac{5pi}{6}$ on the unit circle are:

$ left( -frac{sqrt{3}}{2}, frac{1}{2}
ight) $

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