Find the coordinates of the point on the unit circle at $frac{3pi}{4}$ radians
Answer 1
The unit circle has a radius of 1 and can be represented by the equation:
$ x^2 + y^2 = 1 $
At an angle of $\frac{3\pi}{4}$ radians, the coordinates can be determined using the sine and cosine functions:
$ x = \cos\left(\frac{3\pi}{4}\right) = -\frac{\sqrt{2}}{2} $
$ y = \sin\left(\frac{3\pi}{4}\right) = \frac{\sqrt{2}}{2} $
Therefore, the coordinates are:
$ \left( -\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right) $
Answer 2
For the unit circle at $frac{3pi}{4}$ radians,
$ x = cosleft(frac{3pi}{4}
ight) = -frac{sqrt{2}}{2} $
$ y = sinleft(frac{3pi}{4}
ight) = frac{sqrt{2}}{2} $
So, the coordinates are:
$ left( -frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight) $
Answer 3
At $frac{3pi}{4}$ radians, the coordinates are:
$ left( -frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight) $
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