Find the coordinates of the point at $45^circ$ on the unit circle.
Answer 1
William King
The unit circle has a radius of 1. At an angle of $45^\circ$, the coordinates of the point can be found using the cosine and sine functions:
$ x = \cos(45^\circ) = \frac{\sqrt{2}}{2} $
$ y = \sin(45^\circ) = \frac{\sqrt{2}}{2} $
Therefore, the coordinates are $(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$.
Answer 2
Daniel Carter
The unit circle’s radius is 1. For an angle of $45^circ$, we use the cosine and sine functions to determine the coordinates:
$ x = cos(45^circ) = frac{sqrt{2}}{2} $
$ y = sin(45^circ) = frac{sqrt{2}}{2} $
Thus, the coordinates at $45^circ$ are $(frac{sqrt{2}}{2}, frac{sqrt{2}}{2})$.
Answer 3
Mia Harris
For $45^circ$ on the unit circle:
$ x = cos(45^circ) = frac{sqrt{2}}{2} $
$ y = sin(45^circ) = frac{sqrt{2}}{2} $
The coordinates are $(frac{sqrt{2}}{2}, frac{sqrt{2}}{2})$.
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