Find the coordinates of points on the unit circle corresponding to an angle $ heta$ in a flipped configuration.
Answer 1
Given a unit circle, we need to find the coordinates of points corresponding to the angle $\theta = \frac{5\pi}{4}$, but with the configuration flipped over the x-axis.
In the standard unit circle, the point corresponding to $\theta = \frac{5\pi}{4}$ is:
$\left(\cos \frac{5\pi}{4}, \sin \frac{5\pi}{4}\right)$
Using the trigonometric values:
$\left(-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2}\right)$
Since the configuration is flipped over the x-axis, we change the sign of the y-coordinate:
$\left(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)$
Thus, the coordinates are:
$\boxed{\left(-\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)}$
Answer 2
Consider the flipped unit circle and the angle $ heta = frac{5pi}{4}$.
Normally, the coordinates on the unit circle are:
$left(cos frac{5pi}{4}, sin frac{5pi}{4}
ight)$
Evaluating this, we get:
$left(-frac{sqrt{2}}{2}, -frac{sqrt{2}}{2}
ight)$
With the flipped configuration over the x-axis, we invert the y-coordinate’s sign:
$left(-frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)$
Hence, the coordinates in the flipped configuration are:
$oxed{left(-frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)}$
Answer 3
Flipped unit circle with angle $ heta = frac{5pi}{4}$.
Original coordinates:
$left(-frac{sqrt{2}}{2}, -frac{sqrt{2}}{2}
ight)$
After flipping over the x-axis:
$left(-frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)$
Result:
$oxed{left(-frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)}$
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