Find the coordinates of a point on the unit circle with an angle of $ frac{pi}{4} $ radians
Answer 1
First, we need to recall that the unit circle is a circle with a radius of 1 centered at the origin.
For an angle of $ \frac{\pi}{4} $ radians, we can use the sine and cosine functions to find the coordinates.
The x-coordinate is given by $ \cos( \frac{\pi}{4} ) = \frac{\sqrt{2}}{2} $.
The y-coordinate is given by $ \sin( \frac{\pi}{4} ) = \frac{\sqrt{2}}{2} $.
Therefore, the coordinates of the point are $ \left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right) $.
Answer 2
To find the coordinates of a point on the unit circle for an angle of $ frac{pi}{4} $ radians, we will use trigonometric functions.
The cosine function gives us the x-coordinate: $ cos( frac{pi}{4} ) = frac{sqrt{2}}{2} $.
The sine function gives us the y-coordinate: $ sin( frac{pi}{4} ) = frac{sqrt{2}}{2} $.
Thus, the coordinates of the point are $ left( frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight) $.
Answer 3
The coordinates of a point on the unit circle for an angle of $ frac{pi}{4} $ radians can be found using trigonometric functions.
The x-coordinate is $ cos( frac{pi}{4} ) = frac{sqrt{2}}{2} $.
The y-coordinate is $ sin( frac{pi}{4} ) = frac{sqrt{2}}{2} $.
Therefore, the coordinates are $ left( frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight) $.
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