Determine the tangent values for the primary angles on the unit circle

To determine the tangent values for the primary angles on the unit circle, we need to evaluate the tangent function at

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, \frac{\pi}{6}, \frac{\pi}{4}, \frac{\pi}{3}, \frac{\pi}{2}, \pi, \frac{3\pi}{2}$ and $2\pi$.

$ \text{tan}(0) = 0 $

$ \text{tan}\left(\frac{\pi}{6}\right) = \frac{1}{\sqrt{3}} $

$ \text{tan}\left(\frac{\pi}{4}\right) = 1 $

$ \text{tan}\left(\frac{\pi}{3}\right) = \sqrt{3} $

$ \text{tan}\left(\frac{\pi}{2}\right) = \text{undefined} $

$ \text{tan}(\pi) = 0 $

$ \text{tan}\left(\frac{3\pi}{2}\right) = \text{undefined} $

$ \text{tan}(2\pi) = 0 $

To find the tangent values for the primary angles on the unit circle:

$ ext{tan}(0) = 0 $

$ ext{tan}left(frac{pi}{6}
ight) = frac{1}{sqrt{3}} $

$ ext{tan}left(frac{pi}{4}
ight) = 1 $

$ ext{tan}left(frac{pi}{3}
ight) = sqrt{3} $

$ ext{tan}(frac{pi}{2}) = ext{undefined} $

$ ext{tan}(pi) = 0 $

Here are the tangent values for primary angles on the unit circle:

$ ext{tan}(0) = 0 $

$ ext{tan}left(frac{pi}{6}
ight) = frac{1}{sqrt{3}} $

$ ext{tan}left(frac{pi}{4}
ight) = 1 $

$ ext{tan}(pi) = 0 $

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