Determine the sine and cosine of the angle $frac{pi}{4}$ on the unit circle.
Answer 1
To find the sine and cosine of the angle $\frac{\pi}{4}$ on the unit circle, we use the definitions of sine and cosine for the unit circle.
For an angle $\theta$ in the unit circle, $\cos(\theta)$ is the x-coordinate and $\sin(\theta)$ is the y-coordinate of the corresponding point.
At $\theta = \frac{\pi}{4}$, the coordinates are known to be $\left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right)$.
Thus,
$ \cos\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2} $
and
$ \sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2} $
Answer 2
The unit circle allows us to determine the sine and cosine for the angle $frac{pi}{4}$. In the unit circle, the coordinates of the point where the terminal side of the angle intersects the circle give the cosine and sine of the angle.
Specifically,
$ cosleft(frac{pi}{4}
ight) = frac{sqrt{2}}{2} $
and
$ sinleft(frac{pi}{4}
ight) = frac{sqrt{2}}{2} $
The coordinates of the point are $left(frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)$, confirming that:
$ cosleft(frac{pi}{4}
ight) = frac{sqrt{2}}{2} $
$ sinleft(frac{pi}{4}
ight) = frac{sqrt{2}}{2} $
Answer 3
The angle $frac{pi}{4}$ on the unit circle has coordinates:
$ left(frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight) $
Therefore,
$ cosleft(frac{pi}{4}
ight) = frac{sqrt{2}}{2} $
and
$ sinleft(frac{pi}{4}
ight) = frac{sqrt{2}}{2} $
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