$ ext{Determine the Quadrant of a Point on the Unit Circle}$
Answer 1
Emily Hall
$\text{To determine the quadrant of a point } (x, y) \text{ on the unit circle, first consider the angle } \theta \text{ in radians.}$
$\text{For example, if } \theta = \frac{3\pi}{4}, \text{ we need to identify which quadrant this angle falls into.}$
$\text{Since } \theta \text{ is between } \frac{\pi}{2} \text{ and } \pi, \text{ it falls into the second quadrant. Therefore, the point is in Quadrant II.}$
Answer 2
Isabella Walker
$ ext{To find the quadrant of a point } (x, y) ext{ on the unit circle, consider the angle } heta. ext{ For instance, if } heta = -frac{pi}{3}, ext{ evaluate where this angle lies.}$
$ heta = -frac{pi}{3} ext{ means } heta ext{ is in the fourth quadrant because it is between } -frac{pi}{2} ext{ and } 0. ext{ Hence, the point is in Quadrant IV.}$
Answer 3
Henry Green
$ ext{Given } heta = frac{5pi}{6}, ext{ the angle lies between } frac{pi}{2} ext{ and } pi, ext{ so the point is in Quadrant II.}$
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