Homework

Find the value of the tangent function at multiple angles using the unit circle

Let

Find the values of sin(A), cos(B), and tan(C) on the unit circle given specific conditions

Consider the unit circle centered at the origin $(0,0)$ in the coordinate plane. Given that $A$, $B$, and $C$ are angles in the unit circle, find $\sin(A)$, $\cos(B)$, and $\tan(C)$ if the following conditions are met:

1) $A = \pi/3$

2) $B = 3\pi/4$

3) $C = 5\pi/6$

Answer:

1) For $A = \pi/3$:

$$ \sin(A) = \sin(\pi/3) = \frac{\sqrt{3}}{2} $$

2) For $B = 3\pi/4$:

$$ \cos(B) = \cos(3\pi/4) = -\frac{\sqrt{2}}{2} $$

3) For $C = 5\pi/6$:

$$ \tan(C) = \tan(5\pi/6) = -\frac{1}{\sqrt{3}} $$

Find the equation of the unit circle

The unit circle is defined as the set of all points in the coordinate plane that are exactly one unit away from the origin. The equation of the unit circle can be derived using the Pythagorean theorem. For a point $(x, y)$ on the circle:

$$ x^2 + y^2 = 1 $$

This equation represents all the points $(x, y)$ that satisfy the condition of being one unit away from the origin.

Identify the coordinates of the point on the unit circle at angle 7π/6

To find the coordinates of the point on the unit circle at angle $ \frac{7\pi}{6} $, use the unit circle values:

$$ \frac{7\pi}{6} $$

is in the third quadrant, where both sine and cosine are negative. The reference angle is $ \frac{\pi}{6} $, which corresponds to the coordinates:

$$ (\cos(\pi/6), \sin(\pi/6)) = (\frac{\sqrt{3}}{2}, \frac{1}{2}) $$

Since it is in the third quadrant, the coordinates are:

$$ \left(-\frac{\sqrt{3}}{2}, -\frac{1}{2}\right) $$

The final coordinates are:

$$ \left(-\frac{\sqrt{3}}{2}, -\frac{1}{2}\right) $$

Determine the angle θ in degrees for which the point (cos(θ), sin(θ)) is closest to the point (1/2, -sqrt(3)/2) on the unit circle

To find θ in degrees, we first find the angle whose coordinates on the unit circle are closest to (1/2, -√3/2). This point corresponds to the angle -60 degrees or 300 degrees.

The point (cos(θ), sin(θ)) that is closest must satisfy the equation:

$$ \cos(\theta) = \frac{1}{2} \text{ and } \sin(\theta) = -\frac{\sqrt{3}}{2} $$

Thus, the angle θ is:

$$ \theta = 300° $$

Find the secant of the angle when the point on the unit circle is at (sqrt(3)/2, 1/2)

Given the point $ \left(\frac{\sqrt{3}}{2}, \frac{1}{2}\right) $ on the unit circle, we need to find the secant of the corresponding angle $ \theta $. Recall that $ \sec(\theta) = \frac{1}{\cos(\theta)} $ and $ \cos(\theta) $ is the x-coordinate.

So, $ \cos(\theta) = \frac{\sqrt{3}}{2} $. Hence,

$$ \sec(\theta) = \frac{1}{\cos(\theta)} = \frac{1}{\frac{\sqrt{3}}{2}} = \frac{2}{\sqrt{3}} = \frac{2 \sqrt{3}}{3} $$

Determine the coordinates of a point on the unit circle with an angle of π/4

The unit circle is a circle with a radius of 1 centered at the origin (0, 0).

The coordinates of a point on the unit circle with an angle $ \frac{\pi}{4} $ are found using trigonometric functions:

$$ x = \cos \left( \frac{\pi}{4} \right) = \frac{\sqrt{2}}{2} $$

$$ y = \sin \left( \frac{\pi}{4} \right) = \frac{\sqrt{2}}{2} $$

Therefore, the coordinates are $ \left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right) $.

Find the exact values of sin(x), cos(x), and tan(x) for x = 7π/6 using the unit circle

To find the exact values of $ \sin(x) $, $ \cos(x) $, and $ \tan(x) $ for $ x = \frac{7\pi}{6} $, follow these steps:

The angle $ \frac{7\pi}{6} $ is in the third quadrant.

For the sine function:

$$ \sin\left(\frac{7\pi}{6}\right) = -\sin\left(\frac{\pi}{6}\right) = -\frac{1}{2} $$

For the cosine function:

$$ \cos\left(\frac{7\pi}{6}\right) = -\cos\left(\frac{\pi}{6}\right) = -\frac{\sqrt{3}}{2} $$

For the tangent function:

$$ \tan\left(\frac{7\pi}{6}\right) = \frac{\sin\left(\frac{7\pi}{6}\right)}{\cos\left(\frac{7\pi}{6}\right)} = \frac{-\frac{1}{2}}{-\frac{\sqrt{3}}{2}} = \frac{1}{\sqrt{3}} = \frac{\sqrt{3}}{3} $$

Find the sine and cosine values at the angle pi/4

At the angle $ \frac{\pi}{4} $, the coordinates on the unit circle are:

$$ \left( \cos\left( \frac{\pi}{4} \right), \sin\left( \frac{\pi}{4} \right) \right) $$

Using the unit circle values:

$$ \cos\left( \frac{\pi}{4} \right) = \frac{\sqrt{2}}{2}, \;\sin\left( \frac{\pi}{4} \right) = \frac{\sqrt{2}}{2} $$