Unit Circle

Find the exact value of sin(π/4) on the unit circle

To find the exact value of $ \sin(\frac{\pi}{4}) $ on the unit circle, we recognize that $ \frac{\pi}{4} $ is equivalent to $ 45^{\circ} $.

On the unit circle, the coordinates for $ \frac{\pi}{4} $ are $ \left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right) $.

The sine value is the y-coordinate, so:

$$ \sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2} $$

Find the value of sin(θ) and cos(θ) where θ = π/3 using the unit circle

To find the values of $ \sin(\theta) $ and $ \cos(\theta) $ where $ \theta = \frac{\pi}{3} $, we use the unit circle.

On the unit circle, the coordinates of the point corresponding to $ \theta = \frac{\pi}{3} $ are:

$$ \left(\cos\left(\frac{\pi}{3}\right), \sin\left(\frac{\pi}{3}\right)\right) $$

From the unit circle, these values are:

$$ \cos\left(\frac{\pi}{3}\right) = \frac{1}{2} $$

$$ \sin\left(\frac{\pi}{3}\right) = \frac{\sqrt{3}}{2} $$

Find the value of tan(x) for x = pi/4

To find the value of $ \tan(x) $ when $ x = \frac{\pi}{4} $, we use the unit circle chart.

For $ x = \frac{\pi}{4} $, the coordinates on the unit circle are (\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}).

The tangent function is defined as:

$$ \tan(x) = \frac{\sin(x)}{\cos(x)} $$

So,

$$ \tan\left( \frac{\pi}{4} \right) = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1 $$

Explain the concept of a unit circle, including its importance in trigonometry and how it relates to the coordinates of points on the circle

A unit circle is a circle with a radius of 1, centered at the origin of a coordinate system. The equation of the unit circle is given by:

$$ x^2 + y^2 = 1 $$

The unit circle is fundamental in trigonometry as it defines the sine and cosine functions for all real numbers. For any angle $\theta$, the coordinates of the corresponding point on the unit circle are $(\cos(\theta), \sin(\theta))$. These coordinates are derived from the definitions:

$$ \cos(\theta) = \frac{x}{1} = x $$

$$ \sin(\theta) = \frac{y}{1} = y $$

Additionally, the unit circle helps in visualizing and understanding periodic properties of trigonometric functions and their symmetries.

Find the angle in degrees corresponding to 7π/6 radians on the unit circle

To convert $\frac{7\pi}{6}$ radians to degrees, we use the conversion factor:

$$ 180^{\circ} = \pi \text{ radians} $$

Thus,

$$ \frac{7\pi}{6} \times \frac{180^{\circ}}{\pi} = 210^{\circ} $$

The angle in degrees is:

$$ 210^{\circ} $$

Find the coordinates on the unit circle where the tangent of the angle is 1

To find the coordinates on the unit circle where $ \tan(\theta) = 1 $, we need to determine the angles $\theta $ for which this condition holds. We know that:

$$ \tan(\theta) = \frac {\sin(\theta)}{\cos(\theta)} $$

For the tangent to be 1, the sine and cosine must be equal. This occurs at angles:

$$ \theta = \frac {\pi}{4} \text{ and } \theta = \frac {5\pi}{4} $$

Now, we find the coordinates on the unit circle for these angles:

$$ \text{At } \theta = \frac {\pi}{4}, \text{ the coordinates are } \left( \frac {\sqrt {2}}{2}, \frac {\sqrt {2}}{2} \right) $$

$$ \text{At } \theta = \frac {5\pi}{4}, \text{ the coordinates are } \left( -\frac {\sqrt {2}}{2}, -\frac {\sqrt {2}}{2} \right) $$

Thus, the coordinates on the unit circle where $ \tan(\theta) = 1 $ are:

$$ \left( \frac {\sqrt {2}}{2}, \frac {\sqrt {2}}{2} \right) $$

and

$$ \left( -\frac {\sqrt {2}}{2}, -\frac {\sqrt {2}}{2} \right) $$

Find the sine value at π/3 on the unit circle

To find the sine value at $ \frac{\pi}{3} $ on the unit circle, we use the unit circle definition. The angle $ \frac{\pi}{3} $ is equivalent to 60 degrees.

On the unit circle, the sine value at 60 degrees is:

$$ \sin \left( \frac{\pi}{3} \right) = \frac{\sqrt{3}}{2} $$

Find the sine and cosine of the angle θ on the unit circle when θ = 5π/4

To find the sine and cosine of the angle $\theta = \frac{5\pi}{4}$ on the unit circle, we use the definitions of the trigonometric functions on the unit circle. The angle $\frac{5\pi}{4}$ is in the third quadrant.

For angles in the third quadrant, both sine and cosine are negative. The reference angle for $\theta = \frac{5\pi}{4}$ is $\frac{\pi}{4}$.

The sine and cosine of $\frac{\pi}{4}$ are both $\frac{\sqrt{2}}{2}$.

Thus:

$$\sin\left(\frac{5\pi}{4}\right) = -\frac{\sqrt{2}}{2}$$

$$\cos\left(\frac{5\pi}{4}\right) = -\frac{\sqrt{2}}{2}$$

Find the coordinates of a point on the unit circle that corresponds to an angle of π/3 radians

To find the coordinates of a point on the unit circle corresponding to an angle of $ \frac{\pi}{3} $ radians:

We can use the unit circle definitions for sine and cosine.

$$ x = \cos \left( \frac{\pi}{3} \right) $$

$$ y = \sin \left( \frac{\pi}{3} \right) $$

Since $ \cos \left( \frac{\pi}{3} \right) = \frac{1}{2} $ and $ \sin \left( \frac{\pi}{3} \right) = \frac{\sqrt{3}}{2} $, the coordinates are:

$$ \left( \frac{1}{2}, \frac{\sqrt{3}}{2} \right) $$

Find the angle θ in radians where cos(θ) = -1/2 and 0 ≤ θ < 2π

To find the angle $ \theta $ in radians where $ \cos(\theta) = -\frac{1}{2} $ and $ 0 \leq \theta < 2\pi $, we look for the points on the unit circle where the x-coordinate is -1/2.

These points correspond to angles in the second and third quadrants.

In the second quadrant, the angle is:

$$ \theta = \pi – \frac{\pi}{3} = \frac{2\pi}{3} $$

In the third quadrant, the angle is:

$$ \theta = \pi + \frac{\pi}{3} = \frac{4\pi}{3} $$

Therefore, the angles are:

$$ \theta = \frac{2\pi}{3} \text{ and } \frac{4\pi}{3} $$