Unit Circle

Find the value of the cosecant function for an angle in the unit circle

Answer 1:

Given an angle \( \theta \) in the unit circle, we need to find the value of \( \csc(\theta) \). Recall that \( \csc(\theta) = \frac{1}{\sin(\theta)} \).

Let’s consider \( \theta = \frac{5\pi}{6} \). First, we find \( \sin\left(\frac{5\pi}{6}\right) \). Since \( \sin\left(\frac{5\pi}{6}\right) = \sin\left(\pi – \frac{\pi}{6}\right) = \sin\left(\frac{\pi}{6}\right) \), we have \( \sin\left(\frac{5\pi}{6}\right) = \frac{1}{2} \).

Thus, \( \csc\left(\frac{5\pi}{6}\right) = \frac{1}{\sin\left(\frac{5\pi}{6}\right)} = \frac{1}{\frac{1}{2}} = 2 \).

Find the value of cotangent at $\frac{\pi}{4}$ on the unit circle

To find $\cot \left( \frac{\pi}{4} \right)$, we use the definition of cotangent in terms of sine and cosine.

$$\cot \theta = \frac{\cos \theta}{\sin \theta}$$

For $\theta = \frac{\pi}{4}$, we have:

$$\cos \left( \frac{\pi}{4} \right) = \frac{\sqrt{2}}{2}$$

$$\sin \left( \frac{\pi}{4} \right) = \frac{\sqrt{2}}{2}$$

Therefore,

$$\cot \left( \frac{\pi}{4} \right) = \frac{\cos \left( \frac{\pi}{4} \right)}{\sin \left( \frac{\pi}{4} \right)} = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$$

Calculate the exact value of cos(5π/6) using the unit circle

We must first determine the reference angle for $ \frac{5\pi}{6} $. This angle is in the second quadrant.

The reference angle for $ \frac{5\pi}{6} $ is $ \pi – \frac{5\pi}{6} = \frac{\pi}{6} $.

In the second quadrant, the cosine function is negative. Thus,

$$ \cos(\frac{5\pi}{6}) = -\cos(\frac{\pi}{6}) $$

We know that $ \cos(\frac{\pi}{6}) = \frac{\sqrt{3}}{2} $, therefore,

$$ \cos(\frac{5\pi}{6}) = -\frac{\sqrt{3}}{2} $$

Find the Equations of Circles on the Unit Circle

To find the equations of all circles on the unit circle, we start with the general form of a circle’s equation:

$$ (x – h)^2 + (y – k)^2 = r^2$$

Since we are dealing with the unit circle, the radius r is 1. Thus, the equation simplifies to:

$$ (x – h)^2 + (y – k)^2 = 1$$

Here, (h, k) represents the center of the circle. Because the unit circle is centered at the origin (0, 0), h and k are both 0. Therefore, the equation of the unit circle is:

$$ x^2 + y^2 = 1$$

Find the value of tan(θ) where θ is a special angle on the unit circle

To find the value of $\tan(\theta)$ where $\theta$ is a special angle on the unit circle, we use the definition $\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$.

For $\theta = \frac{\pi}{4}$, the sine and cosine values are both $\frac{\sqrt{2}}{2}$.

Therefore, $\tan(\frac{\pi}{4}) = \frac{\frac{\sqrt{2}}{2}}{\frac{\sqrt{2}}{2}} = 1$.

Find the values of sin(π/4) and cos(π/4) using the unit circle

Using the unit circle, we can find the values of $\sin(\frac{\pi}{4})$ and $\cos(\frac{\pi}{4})$ by locating the angle $\frac{\pi}{4}$ radians. This angle corresponds to a 45-degree angle in the unit circle.

At this angle, both the x-coordinate (which represents $\cos(\frac{\pi}{4})$) and the y-coordinate (which represents $\sin(\frac{\pi}{4})$) are equal to $\frac{\sqrt{2}}{2}$.

Thus,

$$\sin(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$$

$$\cos(\frac{\pi}{4}) = \frac{\sqrt{2}}{2}$$

Find the Cosine of 45 Degrees

To find the cosine of $45^\circ$, we use the unit circle. On the unit circle, the coordinates of the point where the terminal side of the $45^\circ$ angle intersects the circle are $(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2})$. The cosine of an angle is equal to the x-coordinate of this point.

Therefore,

$$\cos(45^\circ) = \frac{\sqrt{2}}{2}$$

Problem: Calculate the Sine, Cosine, and Tangent Values of Specific Angles on the Unit Circle

Let’s determine the sine, cosine, and tangent values for the angle θ = 225° on the unit circle.

First, convert the angle to radians:

$$ θ = 225° = \frac{225π}{180} = \frac{5π}{4} radians $$

Using the properties of the unit circle, we know:

$$ \cos(\frac{5π}{4}) = -\frac{\sqrt{2}}{2} $$

$$ \sin(\frac{5π}{4}) = -\frac{\sqrt{2}}{2} $$

$$ \tan(\frac{5π}{4}) = \frac{\sin(\frac{5π}{4})}{\cos(\frac{5π}{4})} = \frac{-\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = 1 $$

Thus, the sine, cosine, and tangent values for θ = 225° are:

$$ \sin(225°) = -\frac{\sqrt{2}}{2} $$

$$ \cos(225°) = -\frac{\sqrt{2}}{2} $$

$$ \tan(225°) = 1 $$

Calculating the Tangent Value of an Angle in the Unit Circle

Let’s consider an angle $ \theta $ in the unit circle. The coordinates of a point on the unit circle are given by $(\cos \theta, \sin \theta)$. The tangent of the angle $ \theta $ is defined as:

$$\tan \theta = \frac{\sin \theta}{\cos \theta}$$

Suppose $\theta = \frac{5\pi}{4}$, we need to find the value of $\tan \theta$. From the unit circle, we have:

$\sin \frac{5\pi}{4} = -\frac{\sqrt{2}}{2}$

$\cos \frac{5\pi}{4} = -\frac{\sqrt{2}}{2}$

Thus,

$$\tan \frac{5\pi}{4} = \frac{-\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}} = 1$$

Determine the tangent values for specific angles on the unit circle

To determine the tangent values for angles $\frac{\pi}{4}$, $\frac{2\pi}{3}$, and $\frac{5\pi}{6}$ on the unit circle, follow these steps:

1. For the angle $\frac{\pi}{4}$: $$\tan \left( \frac{\pi}{4} \right) = 1$$

2. For the angle $\frac{2\pi}{3}$: $$\tan \left( \frac{2\pi}{3} \right) = -\sqrt{3}$$

3. For the angle $\frac{5\pi}{6}$: $$\tan \left( \frac{5\pi}{6} \right) = -\frac{\sqrt{3}}{3}$$

Thus, the tangent values are $1$, $-\sqrt{3}$, and $-\frac{\sqrt{3}}{3}$ respectively.