Determine the coordinates on the unit circle where the tangent line passes through the point (1,2)
To find the points on the unit circle where the tangent line passes through the point $(1, 2)$, we can use the following steps:
1. The equation of the unit circle is given by $$x^2 + y^2 = 1$$.
2. The slope of the tangent line at any point $(a, b)$ on the circle is $$-a/b$$.
3. The equation of the tangent line at $(a, b)$ can be written as:
$$y – b = -\frac{a}{b}(x – a)$$
4. Substitute the point $(1, 2)$ into this equation to find $(a, b)$:
$$2 – b = -\frac{a}{b}(1 – a)$$
5. Simplify and solve for $(a, b)$.
After solving, we get:
$$a = \frac{\sqrt{2}}{3}$$ and $$b = \frac{\sqrt{2}}{3}$$.
Thus, the coordinates are: $$(\frac{\sqrt{2}}{3}, \frac{\sqrt{2}}{3})$$ and $$(\frac{-\sqrt{2}}{3}, \frac{-\sqrt{2}}{3})$$.