If point $P$ on the unit circle is flipped over the $y$-axis, what will be the coordinates of point $P$ if it initially lies on the point $(frac{sqrt{3}}{2}, frac{1}{2})$?
Answer 1
Mia Harris
Initial coordinates of point $P$ are $(\frac{\sqrt{3}}{2}, \frac{1}{2})$. When flipped over the $y$-axis, the x-coordinate becomes its negative value while the y-coordinate remains the same. Therefore, the new coordinates of point $P$ are:
$(-\frac{\sqrt{3}}{2}, \frac{1}{2})$
Answer 2
Matthew Carter
Given point $P$ initial coordinates $(frac{sqrt{3}}{2}, frac{1}{2})$. Flipping this point over the $y$-axis means changing the sign of the x-coordinate while keeping the y-coordinate unchanged. Thus, the new coordinates are:
$(-frac{sqrt{3}}{2}, frac{1}{2})$
Answer 3
Charlotte Davis
For point $P$ with coordinates $(frac{sqrt{3}}{2}, frac{1}{2})$, flipping over the $y$-axis results in coordinates:
$(-frac{sqrt{3}}{2}, frac{1}{2})$
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