Given that $ csc( heta) = 2 $ and $ heta $ lies in the second quadrant, find the exact value of $ heta $ and verify using trigonometric identities.
Answer 1
Given:
$ \csc(\theta) = 2 $
Since \( \csc(\theta) = \frac{1}{\sin(\theta)} \), we get:
$ \sin(\theta) = \frac{1}{2} $
In the second quadrant, angle \( \theta \) where \( \sin(\theta) = \frac{1}{2} \) is:
$ \theta = 180^\circ – 30^\circ = 150^\circ $
Converting to radians:
$ \theta = \pi – \frac{\pi}{6} = \frac{5\pi}{6} $
Verification:
$ \csc(\frac{5\pi}{6}) = \frac{1}{\sin(\frac{5\pi}{6})} = \frac{1}{\frac{1}{2}} = 2 $
Thus, the exact value of \( \theta \) is:
$ \boxed{\frac{5\pi}{6}} $
Answer 2
Given:
$ csc( heta) = 2 $
We know:
$ csc( heta) = frac{1}{sin( heta)} $
Thus:
$ sin( heta) = frac{1}{2} $
In the second quadrant, ( heta ) is:
$ heta = 180^circ – 30^circ = 150^circ $
Converting to radians:
$ heta = frac{5pi}{6} $
To verify:
$ csc(frac{5pi}{6}) = csc(150^circ) = 2 $
Thus, the exact value of ( heta ) is:
$ oxed{frac{5pi}{6}} $
Answer 3
Given:
$ csc( heta) = 2 $
Since:
$ csc( heta) = frac{1}{sin( heta)} $
Then:
$ sin( heta) = frac{1}{2} $
In the second quadrant:
$ heta = 150^circ = frac{5pi}{6} $
Verify:
$ csc(150^circ) = 2 $
The exact value of ( heta ) is:
$ oxed{frac{5pi}{6}} $
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