Find the sine, cosine, and tangent of an angle on the unit circle at $45^circ$.
Answer 1
To find the sine, cosine, and tangent of a $45^\circ$ angle, we start by remembering that on the unit circle:
$\sin(45^\circ) = \frac{\sqrt{2}}{2}$
$\cos(45^\circ) = \frac{\sqrt{2}}{2}$
$\tan(45^\circ) = 1$
Therefore, the sine, cosine, and tangent of $45^\circ$ are $\frac{\sqrt{2}}{2}$, $\frac{\sqrt{2}}{2}$, and $1$ respectively.
Answer 2
On the unit circle, the coordinates of the point corresponding to $45^circ$ are:
$left( cos(45^circ), sin(45^circ)
ight) = left( frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)$
Since the tangent function is the ratio of the sine to the cosine:
$ an(45^circ) = frac{sin(45^circ)}{cos(45^circ)} = frac{frac{sqrt{2}}{2}}{frac{sqrt{2}}{2}} = 1$
Thus, the sine, cosine, and tangent of $45^circ$ are $frac{sqrt{2}}{2}$, $frac{sqrt{2}}{2}$, and $1$ respectively.
Answer 3
For $45^circ$:
$sin(45^circ) = frac{sqrt{2}}{2}$
$cos(45^circ) = frac{sqrt{2}}{2}$
$ an(45^circ) = 1$
Therefore, the values are $frac{sqrt{2}}{2}$, $frac{sqrt{2}}{2}$, and $1$ respectively.
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