Find the coordinates of a point on the unit circle where the angle is $45^circ$.
Answer 1
To find the coordinates of a point on the unit circle at an angle of $45^\circ$, we can use the unit circle properties.
The coordinates $(x, y)$ of a point on the unit circle at an angle $\theta$ are given by:
$x = \cos(\theta)$
$y = \sin(\theta)$
For $\theta = 45^\circ$:
$x = \cos(45^\circ) = \frac{\sqrt{2}}{2}$
$y = \sin(45^\circ) = \frac{\sqrt{2}}{2}$
So, the coordinates are:
$\left( \frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2} \right)$
Answer 2
For an angle of $45^circ$ on the unit circle, we can determine the coordinates $(x, y)$ by using the cosine and sine values of the angle.
Using the formulas:
$x = cos( heta)$
$y = sin( heta)$
With $ heta = 45^circ$:
$x = cos(45^circ) = frac{1}{sqrt{2}}$
$y = sin(45^circ) = frac{1}{sqrt{2}}$
Therefore, the coordinates are:
$left( frac{1}{sqrt{2}}, frac{1}{sqrt{2}}
ight)$
Answer 3
For $45^circ$ on the unit circle:
$cos(45^circ) = frac{sqrt{2}}{2}$
$sin(45^circ) = frac{sqrt{2}}{2}$
So the coordinates are:
$left( frac{sqrt{2}}{2}, frac{sqrt{2}}{2}
ight)$
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