Find the coordinates of a point on the unit circle corresponding to an angle of $ frac{5pi}{6} $
Answer 1
Daniel Carter
To find the coordinates of a point on the unit circle at an angle of $ \frac{5\pi}{6} $, we use the unit circle definitions for sine and cosine:
$ \text{cos}(\theta) = \text{x-coordinate} $
$ \text{sin}(\theta) = \text{y-coordinate} $
For $ \frac{5\pi}{6} $:
$ \text{cos}(\frac{5\pi}{6}) = – \frac{\sqrt{3}}{2} $
$ \text{sin}(\frac{5\pi}{6}) = \frac{1}{2} $
So, the coordinates are:
$ \left( -\frac{\sqrt{3}}{2}, \frac{1}{2} \right) $
Answer 2
Mia Harris
To find the coordinates of a point on the unit circle at an angle of $ frac{5pi}{6} $:
$ ext{cos}(frac{5pi}{6}) = – frac{sqrt{3}}{2} $
$ ext{sin}(frac{5pi}{6}) = frac{1}{2} $
So, the coordinates are:
$ left( -frac{sqrt{3}}{2}, frac{1}{2}
ight) $
Answer 3
Maria Rodriguez
The coordinates at an angle of $ frac{5pi}{6} $ are:
$ left( -frac{sqrt{3}}{2}, frac{1}{2}
ight) $
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