Find the coordinates of a point on the unit circle at an angle of $ frac{pi}{6} $
Answer 1
Ava Martin
To find the coordinates of a point on the unit circle at an angle of $ \frac{\pi}{6} $, we use the fact that the coordinates are given by $ ( \cos(\theta), \sin(\theta)) $ where $ \theta $ is the angle:
$ \theta = \frac{\pi}{6} $
Therefore:
$ \cos(\frac{\pi}{6}) = \frac{\sqrt{3}}{2} $
$ \sin(\frac{\pi}{6}) = \frac{1}{2} $
The coordinates are:
$ \left( \frac{\sqrt{3}}{2}, \frac{1}{2} \right) $
Answer 2
Chloe Evans
The coordinates of a point on the unit circle at an angle of $ frac{pi}{6} $ can be found using:
$ cos( heta) $
and
$ sin( heta) $
For $ heta = frac{pi}{6} $:
$ cos(frac{pi}{6}) = frac{sqrt{3}}{2} $
$ sin(frac{pi}{6}) = frac{1}{2} $
The coordinates are:
$ left( frac{sqrt{3}}{2}, frac{1}{2}
ight) $
Answer 3
Charlotte Davis
For $ heta = frac{pi}{6} $, the coordinates are:
$ left( frac{sqrt{3}}{2}, frac{1}{2}
ight) $
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