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Determine the cosine value at specific points on the unit circle
Answer 1 $\text{Consider the point where the angle is } 60^\circ \text{ on the unit circle.}$ $\text{The cosine of } 60^\circ \text{ is given by } \cos(60^\circ) = \frac{1}{2}. $$\text{Therefore, the cosine value at } 60^\circ \text{ on the unit...
Find the sine and cosine values for the angle 5π/6 using the unit circle
Answer 1 First, locate the angle $\frac{5\pi}{6}$ on the unit circle.The angle $\frac{5\pi}{6}$ is in the second quadrant.In the second quadrant, sine is positive and cosine is negative.The reference angle for $\frac{5\pi}{6}$ is $\pi -...
Find the value of tan for given angles on the unit circle
Answer 1 Consider the angle $\theta = \frac{3\pi}{4}$ on the unit circle.First, determine the reference angle. The reference angle for $\frac{3\pi}{4}$ is $\frac{\pi}{4}$.Since $\frac{3\pi}{4}$ is in the second quadrant, tangent is negative.We know...
Cosine Values on the Unit Circle
Answer 1 Consider the point $P(\frac{1}{2}, \frac{\sqrt{3}}{2})$ on the unit circle. Determine the cosine of the angle $\theta$ corresponding to this point.Solution:On the unit circle, the coordinates of a point $P(x, y)$ correspond to $(\cos \theta,...
Find the equation of a circle passing through the point (3, 4) and having its center at the point (1, 2)
Answer 1 The general equation of a circle centered at $(h, k)$ with radius $r$ is: $ (x - h)^2 + (y - k)^2 = r^2 $ Here, the center $(h, k)$ is $(1, 2)$. So the equation becomes: $ (x - 1)^2 + (y - 2)^2 = r^2 $ Since the point $(3, 4)$ lies on the...
Find the slope of the tangent line to the unit circle at the point where $\theta = \frac{\pi}{4}$
Answer 1 To find the slope of the tangent line to the unit circle at the point where $\theta = \frac{\pi}{4}$, we start by finding the coordinates of the point on the unit circle.At $\theta = \frac{\pi}{4}$, the coordinates are: $...